How do you calculate the number of particles in
1.00 mole of nitrogen atoms?
Atomic/Molecular Weight of a substance = 1 Mole
of that substance
1 Mole of any substance = (6.022 x 10^23) particles
so,
For Nitrogen,
Atomic Weight of Nitrogen = 14 gm = 1 mole of Nitrogen
(whatever may be the atomic/molecular weight of a substance, 1 mole of that substance is always equal to the atomic/molecular weight of 1 atom/molecule of that substance.)
so,
no. of particles in 1 mole of nitrogen (or 14gm of nitrogen) is equal to (6.022 x 10^23).
1 Mole of any substance = (6.022 x 10^23) particles
so,
For Nitrogen,
Atomic Weight of Nitrogen = 14 gm = 1 mole of Nitrogen
(whatever may be the atomic/molecular weight of a substance, 1 mole of that substance is always equal to the atomic/molecular weight of 1 atom/molecule of that substance.)
so,
no. of particles in 1 mole of nitrogen (or 14gm of nitrogen) is equal to (6.022 x 10^23).
Can someone please help me with this question
its very very important. If 27.0 g of Fe reacted with an excess of O2, how many
moles of Fe2O3 are formed?
4Fe+ 3O2-->2FeO3
4Fe+ 3O2-->2FeO3
