Can someone please help me with this question its very very important. If 27.0 g of Fe reacted with an excess of O2, how many moles of Fe2O3 are formed?

Can someone please help me with this question its very very important. If 27.0 g of Fe reacted with an excess of O2, how many moles of Fe2O3 are formed? 
4Fe+ 3O2-->2FeO3

The equation should read 4 Fe + 3 O2 -> 2 Fe2O3 
The excess O2 indicates that the amount of Fe2O3 formed is determined by the number of moles of Fe 
The number of moles of Fe is the mass of Fe available divided by the mass of a mole of Fe. This is 27g/56g=0.482 moles 
The number of moles of Fe2O3 is half that number because there are 2 Fe in Fe2O3 
Answer is 0.482 moles/2 = 0.241 moles